ln(x-3)+lnx^2-ln(3x)=2

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Solution for ln(x-3)+lnx^2-ln(3x)=2 equation:


Simplifying
ln(x + -3) + lnx2 + -1ln(3x) = 2

Reorder the terms:
ln(-3 + x) + lnx2 + -1ln(3x) = 2
(-3 * ln + x * ln) + lnx2 + -1ln(3x) = 2
(-3ln + lnx) + lnx2 + -1ln(3x) = 2

Remove parenthesis around (3x)
-3ln + lnx + lnx2 + -1ln * 3x = 2

Reorder the terms for easier multiplication:
-3ln + lnx + lnx2 + -1 * 3ln * x = 2

Multiply -1 * 3
-3ln + lnx + lnx2 + -3ln * x = 2

Multiply ln * x
-3ln + lnx + lnx2 + -3lnx = 2

Reorder the terms:
-3ln + lnx + -3lnx + lnx2 = 2

Combine like terms: lnx + -3lnx = -2lnx
-3ln + -2lnx + lnx2 = 2

Solving
-3ln + -2lnx + lnx2 = 2

Solving for variable 'l'.

Move all terms containing l to the left, all other terms to the right.

Reorder the terms:
-2 + -3ln + -2lnx + lnx2 = 2 + -2

Combine like terms: 2 + -2 = 0
-2 + -3ln + -2lnx + lnx2 = 0

The solution to this equation could not be determined.

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